Precalculus Honors | Standards PC.NR.2 & PC.NR.3
We will explore the geometry and algebra of vectors and complex numbers, focusing on their representations and applications.
A vector represents a quantity with both magnitude (length) and direction.
| Form | Notation | Formula |
|---|---|---|
| Component Form | \(\mathbf{v} = \langle x, y \rangle\) | \(x = v_2 - v_1, y = v_2 - v_1\) |
| Magnitude | \(\|\mathbf{v}\|\) | \(\sqrt{x^2 + y^2}\) |
| Direction Angle | \(\theta\) | \(\tan \theta = \frac{y}{x}\) |
v_mag = Math.sqrt(v_x**2 + v_y**2)
v_ang = Math.atan2(v_y, v_x) * 180 / Math.PI
Plot.plot({
aspectRatio: 1,
x: {domain: [-11, 11], grid: true},
y: {domain: [-11, 11], grid: true},
marks: [
Plot.arrow([[0, 0], [v_x, v_y]], {stroke: "#332288", strokeWidth: 4}),
Plot.text([[v_x, v_y + 1]], {text: [`v = ⟨${v_x}, ${v_y}⟩`], fontSize: 20, fill: "#332288"}),
Plot.text([[-9, 9]], {
text: [`Magnitude: ${v_mag.toFixed(2)} | Angle: ${v_ang.toFixed(1)}°`],
fontSize: 22, fontWeight: "bold", fill: "#117733"
})
]
})To find the resultant vector \(\mathbf{u} + \mathbf{v}\):
Scalar Multiplication: Multiplying a vector by \(k\) changes its magnitude (and direction if \(k < 0\)) but stays on the same line.
r_x = u_x + w_x
r_y = u_y + w_y
Plot.plot({
aspectRatio: 1,
x: {domain: [-1, 10], grid: true},
y: {domain: [-1, 10], grid: true},
marks: [
Plot.arrow([[0, 0], [u_x, u_y]], {stroke: "#117733", strokeWidth: 3}), // u
Plot.arrow([[0, 0], [w_x, w_y]], {stroke: "#44AA99", strokeWidth: 3}), // v
// Parallelogram dashed lines
Plot.line([[u_x, u_y], [r_x, r_y]], {stroke: "#aaa", strokeDasharray: "4"}),
Plot.line([[w_x, w_y], [r_x, r_y]], {stroke: "#aaa", strokeDasharray: "4"}),
// Resultant
Plot.arrow([[0, 0], [r_x, r_y]], {stroke: "#AA4499", strokeWidth: 5}),
Plot.text([[r_x, r_y + 0.5]], {text: ["Resultant u+v"], fill: "#AA4499", fontSize: 20})
]
})1. Find the component form of a vector with magnitude 10 and direction angle \(150^\circ\).
\(x = 10 \cos(150^\circ) = -5\sqrt{3}, \quad y = 10 \sin(150^\circ) = 5\) \(\rightarrow\) \(\langle -5\sqrt{3}, 5 \rangle\)
2. Given \(\mathbf{u} = \langle 2, -3 \rangle\) and \(\mathbf{v} = \langle 5, 4 \rangle\), find \(2\mathbf{u} - \mathbf{v}\).
\(\langle 4, -6 \rangle - \langle 5, 4 \rangle = \langle 4-5, -6-4 \rangle\) \(\rightarrow\) \(\langle -1, -10 \rangle\)
3. An airplane flies at 400 mph at \(N 30^\circ E\). A wind blows at 50 mph from the West. Find the resultant velocity.
\(\mathbf{p} = \langle 400\sin 30, 400\cos 30 \rangle = \langle 200, 346.4 \rangle\) \(\mathbf{w} = \langle 50, 0 \rangle \rightarrow \mathbf{r} = \langle 250, 346.4 \rangle\) \(\text{Mag} \approx 427.2 \text{ mph}\)
The complex number \(z = a + bi\) can be mapped to \((a, b)\) on the complex plane.
| Form | Representation | Conversion |
|---|---|---|
| Rectangular | \(z = a + bi\) | \(a = r \cos \theta, b = r \sin \theta\) |
| Polar | \(z = r(\cos \theta + i \sin \theta)\) | \(r = \sqrt{a^2 + b^2}, \tan \theta = \frac{b}{a}\) |
Insight: These represent the same number because they describe the same point \((a, b)\) using either Cartesian coordinates or distance/angle from the origin.
c_r = Math.sqrt(c_a**2 + c_b**2)
c_theta = Math.atan2(c_b, c_a) * 180 / Math.PI
html`<div style="font-size: 26px; padding: 20px; background: #fdfdfd; border-radius: 10px;">
<p><span style="color:#332288"><b>Rectangular:</b></span> ${c_a} + ${c_b}i</p>
<p><span style="color:#117733"><b>Polar:</b></span> ${c_r.toFixed(2)} [cos(${c_theta.toFixed(1)}°) + i sin(${c_theta.toFixed(1)}°)]</p>
</div>`Plot.plot({
aspectRatio: 1,
x: {domain: [-11, 11], grid: true, label: "Real"},
y: {domain: [-11, 11], grid: true, label: "Imaginary"},
marks: [
Plot.dot([[c_a, c_b]], {r: 6, fill: "#AA4499"}),
Plot.line([[0, 0], [c_a, c_b]], {stroke: "#aaa", strokeDasharray: "3"}),
Plot.text([[c_a, c_b + 0.8]], {text: [`${c_a} + ${c_b}i`], fill: "#AA4499", fontSize: 20})
]
})Polar form makes multiplication and division much simpler:
Multiplication: Multiply \(r\)’s, Add \(\theta\)’s \(z_1 z_2 = r_1 r_2 [\cos(\theta_1 + \theta_2) + i \sin(\theta_1 + \theta_2)]\)
Division: Divide \(r\)’s, Subtract \(\theta\)’s \(\frac{z_1}{z_2} = \frac{r_1}{r_2} [\cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2)]\)
1. Write \(z = -2 + 2i\sqrt{3}\) in polar form.
\(r = \sqrt{(-2)^2 + (2\sqrt{3})^2} = \sqrt{4 + 12} = 4\) \(\theta = \text{atan2}(2\sqrt{3}, -2) = 120^\circ\) \(z = 4(\cos 120^\circ + i \sin 120^\circ)\)
2. Find \(z_1 z_2\) for \(z_1 = 3(\cos 40^\circ + i \sin 40^\circ)\) and \(z_2 = 2(\cos 20^\circ + i \sin 20^\circ)\).
\(r = 3 \cdot 2 = 6, \quad \theta = 40^\circ + 20^\circ = 60^\circ\) \(6(\cos 60^\circ + i \sin 60^\circ) = 3 + 3i\sqrt{3}\)
3. Geometrically, what happens to \(z\) when you find its conjugate \(\bar{z}\)?
The imaginary part changes sign: \((a, b) \rightarrow (a, -b)\). This results in a reflection across the horizontal (real) axis.
| Operation | Algebra | Geometry |
|---|---|---|
| Vector Addition | \(\langle x_1+x_2, y_1+y_2 \rangle\) | Parallelogram/Head-to-Tail |
| Complex Addition | \((a+c) + (b+d)i\) | Parallelogram |
| Complex Mult. | \(r_1r_2, \theta_1+\theta_2\) | Rotation + Scaling |
| Conjugation | \(a - bi\) | Reflection over Real Axis |
\(z = r(\cos \theta + i \sin \theta) \quad \mathbf{v} = \langle \|\mathbf{v}\|\cos \theta, \|\mathbf{v}\|\sin \theta \rangle\) ```